IIT Roorkee JEE Advanced 2026 Cutoff : Check Category-wise and Round-wise Cutoff

The JEE Advanced 2025 Cutoff for IIT Roorkee in the General category ranges from 535 to 17665 for admission to its various programs. The Round 1 closing rank for B.Tech Computer Science Engineering is 535, with the last round rank being 592. For B.Tech Data Science and Artificial Intelligence, the Round 1 cutoff is 710 and the last round cutoff is 845. Other competitive courses such as Electronics & Communication Engineering, Electrical Engineering, and Mechanical Engineering have cutoffs between 1394 and 3897.

Branches including Civil Engineering, Biosciences and Bioengineering, and Geological Technology record cutoffs from 6361 to 10016. Less popular courses like Chemistry and B.Arch have a cutoff range of 10301 to 17665. For OBC-NCL candidates, the Round 1 cutoff is 244 for Computer Science Engineering and the last round cutoff is 6497 for B.Arch. In the SC category, the range is 121 in Round 1 for Computer Science Engineering to 3181 in the last round for B.Arch.

For ST, the range is 74 in Computer Science Engineering to 1492 in BS + MS Physics. Under EWS, the range is 95 in Round 1 for Computer Science Engineering to 2794 in the last round for B.Arch.